Answer
a. $-171 ^{\circ}C$
b. $-191 ^{\circ}C$
c. $410 ^{\circ}C$
d. $-270 ^{\circ}C$
Work Step by Step
$$\frac{T_1}{V_1} = \frac{T_2}{V_2} \longrightarrow \frac{T_1}{V_1}V_2 = T_2$$
$$T_2 = V_2\frac{T_1}{V_1}$$
$T_1/K = 0 + 273 = 273$
a. $$T_2 = (1.50 \space L)\frac{273 \space K}{4.00 \space L} = 102 \space K$$
$T_2/^{\circ}C = 102 - 273 = -171$
$T_2 = -171 ^{\circ} C$
b. $$T_2 = (1.2 \space L)\frac{273 \space K}{4.00 \space L} = 82 \space K$$
$T_2/^{\circ}C = 82 - 273 = -191$
$T_2 = -191 ^{\circ} C$
c. $$T_2 = (10.0 \space L)\frac{273 \space K}{4.00 \space L} = 683 \space K$$
$T_2/^{\circ}C = 683 - 273 = 410$
$T_2 = 410 ^{\circ} C$
d. $$T_2 = (0.0500 \space L)\frac{273 \space K}{4.00 \space L} = 3.41 \space K$$
$T_2/^{\circ}C = 3.41 - 273 = -270$
$T_2 = -270 ^{\circ} C$
