Answer
a. Mass percent(m/m) = $17 \%$ (m/m) $KCl$ solution
b. Mass percent(m/m) = $5.3 \%$ (m/m) $sucrose$ solution
c. Mass percent(m/m) = $10. \%$ (m/m) $CaCl_2$ solution
Work Step by Step
a.
1. Write the expression for the mass percent:
$$Mass \space percent(m/m) = \frac{grams \space of \space solute}{grams \space of \space solution} \times 100\%$$
Mass of solution = Mass of solute + Mass of solvent
$$Mass \space percent(m/m) = \frac{ 25 \space g \space KCl }{( 25 \space g + 125 \space g) \space solution} \times 100\%$$
Mass percent(m/m) = $17 \%$ (m/m) $KCl$ solution
b.
1. Write the expression for the mass percent:
$$Mass \space percent(m/m) = \frac{grams \space of \space solute}{grams \space of \space solution} \times 100\%$$
$$Mass \space percent(m/m) = \frac{ 12 \space g \space sucrose }{ 225 \space g \space tea \space solution} \times 100\%$$
Mass percent(m/m) = $5.3 \%$ (m/m) $sucrose$ solution
c.
1. Write the expression for the mass percent:
$$Mass \space percent(m/m) = \frac{grams \space of \space solute}{grams \space of \space solution} \times 100\%$$
$$Mass \space percent(m/m) = \frac{ 8.0 \space g \space CaCl_2 }{ 80.0 \space g \space CaCl_2 \space solution} \times 100\%$$
Mass percent(m/m) = $10. \%$ (m/m) $CaCl_2$ solution
