Answer
The mass of the iceberg is $233,049.78 kg$
Work Step by Step
First we must convert the units of $ft^{3}$ into units of $cm^{3}$ because we will use the density of ice (i.e. 0.917 kg/cm^3) to determine the mass of the iceberg.
$ {8975 ft^{3}}\times\frac{28316.847 cm^{3}}{1 ft^{3}} = 254143701.8 cm^{3}$. Now we can take our unit of volume and multiply it by the density of water; $254143701.8 cm^{3} \times 0.917 \frac{g}{cm^{3}} = 233049774.6 g$. Lastly we must convert the units of g into kg because the question asks for the mass in kilograms; $233049774.6 g\div1000= 233,049.78 kg$
