Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 2 - Measurement and Problem Solving - Exercises - Problems - Page 50: 49

Answer

a) $256.0$ b) $4.893\times10^{-4}$ c) $2.901\times10^{-4}$ d) $2231\times10^{3}$

Work Step by Step

a) $255.98612$ rounds to $256.0$ if it is rounded to 4 significant figures because rounding the decimal '.98612' simply rounds to the next closest whole number 256 but since the question asks for 4 significant figures, it would be 256.0. b) $4.893\times10^{-4}$ is rounded to 4 significant figures and then put into scientific notation. c) $2.900856\times10^{-4}$ rounds to $2.901\times10^{-4}$ because looking at the fourth digit of 0 and the preceding digit 8, the 0 would round up to 1. d) $2231479$ rounds to $2231\times10^{3}$ because the last digts are smaller than 500 (i.e 479) and therefore, we round down and put into scientific notation.
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