Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 2 - Measurement and Problem Solving - Exercises - Problems - Page 52: 91

Answer

a) $0.000215 km^{2}$. b) $21500 dm^{2}$ c) $2.15 \times10^{6} cm^{2}$.

Work Step by Step

a) To convert from $m^{2}$ to $km^{2}$, we divide the area by 1000000 because $1 km^{2}=1000000 m^{2}$. $215 m^{2}×\frac{1 km^{2} }{1000000 m^{2} }=0.000215 km^{2}$. b) To convert from $m^{2}$ to $dm^{2}$, we multiply the area by 100 because $1 dm^{2}=100 m^{2}$. $215 m^{2}×\frac{100 dm^{2} }{1 m^{2} }=21500 dm^{2}$. c) To convert from $m^{2}$ to $dm^{2}$, we multiply the area by 10000 because $1 cm^{2}=10000 m^{2}$. $215 m^{2}×\frac{10000 cm^{2} }{1 m^{2} }=2.15 \times10^{6} cm^{2}$.
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