Answer
$C_1$
hybridization: $sp^3$
geometry: tetrahedral
bond angle: 109.5
$C_2$
hybridization: $sp^2$
geometry: trigonal planar
bond angle: 120
$N$
hybridization: $sp^2$
electronic geometry: trigonal planar
molecular geometry: bent
bond angle: less than 120
Work Step by Step
The $C_1$ has four domains (four single bonds) around it. Thus, it's tetrahedral and tetrahedral geometry has 109.5 angles.
The $C_2$ three domains (two single and one double bond) around it. Thus, it's trigonal planar and trigonal planar geometry has 120 angles.
The $N$ has 3 domains (one single, one double and one lone pair) around it. The electronic geometry, which includes the lone pairs, is trigonal planar. The molecular geometry, which does not include lone pair, is bent. The angle is less than 120 degrees.