Answer
(i) -212.55 kJ/mol
(ii) -5797.75 kJ/mol
Work Step by Step
Recall that $\Delta_{r}G^{\circ}=\Sigma n_{p}\Delta_{f}G^{\circ}(products)-\Sigma n_{r}\Delta_{f}G^{\circ}(reactants)$
(i) $\Delta_{r}G^{\circ}=[\Delta_{f}G^{\circ}(Zn^{2+},aq)+\Delta_{f}G^{\circ}(Cu, s)]-[\Delta_{f}G^{\circ}(Zn, s)+\Delta_{f}G^{\circ}(Cu^{2+},aq)]$
$=[(-147.06\,kJ/mol)+(0)]-[(0)+(65.49\,kJ/mol)]$
$=-212.55\,kJ/mol$
(ii) $\Delta_{r}G^{\circ}=[12\Delta_{f}G^{\circ}(CO_{2},g)+11\Delta_{f}G^{\circ}(H_{2}O,l)]-[\Delta_{f}G^{\circ}(C_{12}H_{22}O_{11},s)+12\Delta_{f}G^{\circ}(O_{2},g)]$
$=[12(-394.36\,kJ/mol)+11(-237.13)]-[(-1543\,kJ/mol)+12(0)]$
$=-5797.75\,kJ/mol$
