Answer
a) The gibbs free energy of te reaction is: $-0.64 \space kj$ and b) The gibbs free energy of te reaction is: $-0.123 \space kj$
Work Step by Step
Let us consider a reaction $A \to 2B$
Case I: We are given that the extent for a reaction $\triangle \xi = 0.10 mol$
Now, $\triangle_r G =(\dfrac{\partial G}{\partial \xi})_{p, T}$
Plug in the data .
$\partial G=\triangle_r G \cdot \partial \xi=-6.4 \space kj/ mol \times 0.60 space mol=-0.64 kJ$
Case 2: Let us consider a reaction $2A \to B$
We are given that the extent for a reaction $\triangle \xi = 0.051 mol$
Now, $\triangle_r G =(\dfrac{\partial G}{\partial \xi})_{p, T}$
Plug in the data .
$\partial G=\triangle_r G \cdot \partial \xi=-2.41 \space kj/ mol \times 0.051 \space mol=-0.123 kJ$
Therefore, a) The gibbs free energy of the reaction is: $-0.64 \space kj$ and b) The gibbs free energy of the reaction is: $-0.123 \space kj$ .
