Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Foundations - Topic A - Matter - Exercises - Page 23: A.19(b)

Answer

Molecular formula of phosphorous is P4.

Work Step by Step

from Ideal gas law: PV = nRT P = 16 kPa (0.157908 atm) R: gas constant (0.0821 L-atm / mole-K) T: gas temperature in Kelvin (373.15) , but n = m/M .........m: is mass of gas........... M: molar mass of gas PV = (m/M) RT MPV =mRT ..................... M= (m/V)(RT/P) m/V = d, while d is density of gas (mass/volume) so M = (dRT)/P = 0.6388 × 0.0821 × 373.15 / 0.157908 = 123.9 g n of gas = Mass of gas / Molar mass of P (30.97) = 123.9 /30.97 = 4
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