Answer
a) $3.3\times 10^{-8}m$
b) $3.3\times 10^{-2}micron$
c) $1.3\times 10^{-6}in$
Work Step by Step
Circumference of a viroid is approximately 300 times 0.35nm. The diameter is given by $C=pi\times d$
so, $d=C/pi$
a) d=$\frac{300\times 0.35nm\times10^{-9}m}{pi\times 1nm}=3.3\times 10^{-8}m$
b) d=$\frac{300\times 0.35nm\times10^{-3}m}{pi\times 1nm}=3.3\times 10^{-2}micron$
c) d=$\frac{300\times 0.35nm\times10^{-7}m}{pi\times 1nm}\times\frac{1 in}{2.54cm}=1.3\times 10^{-6}in$
