Answer
$1.1\times10^{-9}N$
Work Step by Step
The approximate magnitude of the gravitational force between earth and the spacecraft = $F=G\frac{m_{1}m_{2}}{r^{2}}=(6.674\times10^{-11})\times\frac{825\times 5.974\times 10^{24}}{(17\times10^{12})^{2}}=1.1\times10^{-9}N$
