Answer
The net force on the plane is $0.5~kN$ downward.
Work Step by Step
Let north be the positive direction. We can find the net horizontal force on the plane:
$\sum F_x = 1.2~kN+(-1.2~kN) = 0$
Let upward be the positive direction. We can find the net vertical force on the plane:
$\sum F_y = 15.5~kN+(-16.0~kN) = -0.5~kN$
The net force on the plane is $0.5~kN$ downward.