College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 1 - Measurement and Problem Solving - Learning Path Questions and Exercises - Exercises - Page 29: 24

Answer

The metric football field is larger, and the difference in area is 10056 $ft^{2}$.

Work Step by Step

1 ft = 0.3048 m 100 m = $\frac{100}{0.3048}ft=328\,ft$ (rounded off) 54 m = $\frac{54}{0.3048}ft=177\,ft$ (rounded off) The area is $328 ft \times 177 ft = 58056 ft^{2}$ The area of the football field in Ex. 23= $300 ft\times 160 ft=48000 \,ft^{2}$. Hence, the metric football field is larger and the difference in area is = $58056-48000=10056ft^{2}$
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