Answer
(c) it is reduced to one-ninth of its original value.
Work Step by Step
$F=k\frac{q_{1}q_{2}}{r^{2}}$
When the distance is tripled,
New Force=$k\frac{q_{1}q_{2}}{(3r)^{2}}=\frac{1}{9}F$
Hence, (c) is the answer.
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 15 - Electric Charge, Forces, and Fields - Learning Path Questions and Exercises - Multiple Choice Questions - Page 554: 11
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