Answer
(a) Average speed, $s=0.5\,\mathrm{m/s}$.
(b) Time taken at increase speed is $8.33\,\mathrm{min}$.
Work Step by Step
(a) Average speed,
\begin{align*}
s&=\frac{d}{t}=\frac{300}{10\times60}\\&=0.5\,\mathrm{m/s}
\end{align*}(b) Increased speed, $s'=1.2\times0.5\,\mathrm{m/s}=0.6\,\mathrm{m/s}$
Time taken at this speed,
\begin{align*}
t'&=\frac{d}{s'}=\frac{300}{0.6}\\&=500\,\mathrm{s}\\&=8.33\,\mathrm{min}
\end{align*}