Answer
a). $(1)$ North of east
b). $0.25m/s, at \,\,36.87^{\circ}$ relative with river-bank.
Work Step by Step
a). Since the swimmer is swimming north and the current is pulling him west to east, his direction is north of east.
b). Magnitude of the velocity = $\sqrt (0.15^{2}+0.2^{2})=0.25m/s$
$\theta=tan^{-1}\frac{0.15}{0.2}=36.87^{\circ}$
