College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 136: 26

Answer

273N

Work Step by Step

u=90km/hr=25m/s v=0 time=5.5 s Change in velocity =v-u=0-25=-25m/s Average acceleration =$\frac{change\, in\, velocity}{time}=\frac{-25}{5.5}=-4.55m/s^{2}$ Average force = $mass\times average\, acceleration=60\times4.55=273N$
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