College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 138: 60

Answer

$1.2kg$ in each case.

Work Step by Step

From the problem, $m_{1}gsin37^{\circ}=m_{2}g$ Given $m_{1}=2kg$, $ m_{2}=1.2kg$ For the case of constant velocity the mass will remain same because there is no acceleration hence no external force. The equations will remain same.
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