College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 5 - Work and Energy - Learning Path Questions and Exercises - Exercises - Page 175: 27

Answer

$6J$

Work Step by Step

Work done = area under the curve = Area of first triangle + Area of second triangle + Area of rectangle = $\frac{1}{2}\times20N\times0.3m+\frac{1}{2}\times20N\times0.1m+20N\times0.1m=3+1+2=6J$
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