College Physics (7th Edition)

by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo

Published by Pearson

ISBN 10: 0-32160-183-1

ISBN 13: 978-0-32160-183-4

Chapter 8 - Rotational Motion and Equilibrium - Learning Path Questions and Exercises - Exercises - Page 304: 18

Answer

Fx_{y}m = 164N

Work Step by Step

Tx_{y}m - Tx_{y}m = 0 Fx_{y}m(0.18)sin15^{\circ} = 30kg(9.8m/sx^{y}2)(0.26) Fx_{y}m = 164N

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