Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 19 - The Kinetic Theory of Gases - Questions - Page 577: 9

Answer

$186$ KPa

Work Step by Step

As we know that; $P_2=\frac{P_1V_1T_2}{V_2T_1}$ We plug in the known values to obtain: $P_2=\frac{266(1.64\times 10^{-2})(300)}{(1.67\times 10^{-2})(273)}=287KPa$ Thus, the gauge reading$=287KPa-101KPa=186$KPa
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