Physics (10th Edition)

by Young, David; Stadler, Shane

Published by Wiley

ISBN 10: 1118486897

ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 138: 6

Answer

$a=4.1m/s^2$

Work Step by Step

The arch has a diameter of $5cm$, so its radius $r=2.5cm=0.025m$ Blood's speed $v=0.32m/s$ Therefore, the magnitude of the blood's centripetal acceleration is $$a=\frac{v^2}{r}=4.1m/s^2$$

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