Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 1 - Concepts of Motion - Exercises and Problems - Page 31: 57

Answer

a. $83.3$ $kg/m^3$ b. $0.81$ $g/cm^3$

Work Step by Step

a. The given mass is $0.0179$ kg, and the given volume is $215 cm^3$. The mass density is therefore $0.0179/215$ $kg/cm^3=0.00008325581395$ $kg/cm^3$. Since this is a small number, we convert to $kg/m^3$ remembering that one cubic centimeter is equal to $1*10^{-6}$ cubic meters. Therefore our final answer is: $0.00008325581395 \frac{kg}{cm^3} *\frac{1 cm^3}{10^{-6} m^3}=83.3kg/m^3$, remembering to round to the proper amount of significant figures. b. The given mass is $77$ g, and the given volume is $95 cm^3$. The mass density is therefore $77g/95cm^3=0.81$ $g/cm^3$
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