Answer
For the first 16 sec the rocket has a constant acceleration=a . We need to find this a . The acceleration is 0 at point B as shown in fig. Then from B to C the rocket undergoes deceleration.
Work Step by Step
Using equation of motion find velocity at T= 16 sec in terms of acceleration we get v=16a then find altitude in term of acceleration we get S= 128a. We know the total altitude to be 5100km , total altitude = distance AB+distance CB.
