Answer
$F_x = 77.1~N$
$F_y = 91.9~N$
Work Step by Step
$F_x = F~sin(\theta)$
$F_x = (120~N)~sin(40^{\circ})$
$F_x = 77.1~N$
$F_y = F~cos(\theta)$
$F_y = (120~N)~cos(40^{\circ})$
$F_y = 91.9~N$
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