Answer
$a = (2~\hat{i}-8~\hat{j})~m/s^2$
Work Step by Step
$v(t) = (2t~\hat{i}+(3-t^2)~\hat{j})~m/s$
$a(t) = \frac{dv}{dt}$
$a(t) = (2~\hat{i}-2t~\hat{j})~m/s^2$
At t = 4 s:
$a = (2~\hat{i}-(2)(4)~\hat{j})~m/s^2$
$a = (2~\hat{i}-8~\hat{j})~m/s^2$