Answer
It would take 75 minutes to read all the data on the CD.
Work Step by Step
A CD has (783.216)(8) megabits of data.
The time required to read all this data is:
$\frac{(783.216)(8)}{1.4} = 4475.52~s$
$(4475.52 ~s)(\frac{1 ~min}{60 ~s}) = 75$ minutes
It would take 75 minutes to read all the data on the CD.
