Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 1 - Introduction, Measurement, Estimating - Search and Learn - Page 20: 5

Answer

a) 13.4 b) 49.3

Work Step by Step

a) $$\frac{A_{earth}}{A_{moon}}=\frac{4\pi r^2_{earth}}{4\pi r^2_{moon}}=\frac{r^2_{earth}}{r^2_{moon}}=\frac{(6.38\times 10^3km)^2}{(1.74\times 10^3km)^2}=13.4$$ (b) $$\frac{V_{earth}}{V_{moon}}=\frac{\frac{4}{3}\pi r^3_{earth}}{\frac{4}{3}\pi r^3_{moon}}=\frac{r^3_{earth}}{r^3_{moon}}=\frac{(6.38\times 10^3km)^3}{(1.74\times 10^3km)^3}=49.3$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.