Answer
$4.12*10^{-3} m^3/s$
Work Step by Step
We find the velocity out of the pressure head as:
$v^2= 2gh$
$v=\sqrt{2*9.8*12} = 15.96m/s$
To get $m^3$ we need to multiply by the area
$v * A = 15.96 * (.0185/2)^2 *3.14) = 4.12*10^{-3} m^3/s$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 10 - Fluids - Problems - Page 287: 45
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
