Answer
$1.8m$
Work Step by Step
We can find the required distance as follows:
$d=\frac{v_i^2}{2g(\mu_kcos\theta-sin\theta)}$
We plug in the known values to obtain:
$d=\frac{(1.56)^2}{2(9.81)((0.62)cos 28.4^{\circ}-sin 28.4^{\circ})}$
$d=1.8m$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 8 - Potential Energy and Conservation of Energy - Problems and Conceptual Exercises - Page 249: 84
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