Answer
$100.1kPa$
Work Step by Step
$P_{atmospheric} = density \times gravity \times height = pgh$
$P_{atmospheric} = (13600 kg/m^3)(9.81 m/s^2)(0.75 m)(\dfrac{1 N}{1kg\times m/s^2})(\dfrac{1kPa}{1000N/m^2})$
$P_{atmospheric} = 100.1kPa$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 1 - Introduction and Basic Concepts - Problems - Page 43: 1-51
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