Answer
$η_{th}=40.1\%$
Work Step by Step
In the previous problem, the thermal efficiency of the cycle was determined to be $\mathbf{0 . 3 6 1}(36.1 \%)$. The thermal efficiency with airstandard model is determined from
$$
\eta_{\text {th }}=1-\frac{1}{r_p^{(k-1) / k}}=1-\frac{1}{6^{0.4 / 1.4}}=0.401=\mathbf{4 0 . 1} \%
$$ which is greater than that calculated with gas mixture analysis in the previous problem.
