Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 7 - Entropy - Problems - Page 418: 7-227

Answer

Option (c) $–0.0304$ kJ/K

Work Step by Step

Solved by EES Software. Solutions can be verified by copying-and-pasting the following lines on a blank EES screen. $c=3.65$ "kJ/kg.K" $m=0.12$ "kg" $T_1=25$ "C" $T_2=5$ "C" $S_{\text{change}}=m*C*\ln((T2+273)/(T1+273))$ Option (c) $–0.0304$ kJ/K is correct.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.