Answer
She is correct.
Work Step by Step
As explained on page 559, the units of specific heat are $\frac{J}{kg\cdot K}=\frac{kg\cdot m^2/s^2}{kg\cdot K}$.
This is equivalent to $\frac{m^2/s^2}{C^{\circ}}$.
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 17 - Temperature and Heat - Problems - Discussion Questions - Page 573: Q17.9
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
