Answer
277 nm, ultraviolet.
Work Step by Step
The minimum photon energy is the energy of the covalent bond, 4.48 eV.
$$E= hf=h\frac{c}{\lambda} $$
$$\lambda =\frac{hc}{E}=\frac{1.24\times10^{-6}eV\cdot m}{4.48eV}=277nm$$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 42 - Molecules and Condensed Matter - Problems - Exercises - Page 1434: 42.1
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