Answer
$i_a=-2A$
$i_c=1A$
$i_d=4A$
Work Step by Step
Since $i_a+i_b=0, i_a=-i_b=-2A$
$i_c+i_b=3A$, so $i_c=3-i_b\ A$
$3A+i_e=i_d=3A+1A$
Electrical Engineering: Principles & Applications (6th Edition)
by Hambley, Allan R.
Published by
Prentice Hall
ISBN 10:
0133116646
ISBN 13:
978-0-13311-664-9
Chapter 1 - 1.4 - Problems - Kirchhoff's Current Laws - Page 38: P1.32
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