Answer
$i_c=1A$
$i_e=5A$
$i_f=-3A$
$i_g=-7A$
Work Step by Step
Given $i_a = 2 A, i_b = 3 A, i_d = −5 A$, and $ih = 4 A$.
Apply KCL at each node to find:
$i_c=i_b-i_a=1A$
$i_e=i_c+i_h=5A$
$i_f=i_a+i_d=-3A$
$i_g=i_f-i_h=-7A$
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