Answer
$R=100\Omega$
19% reduction in power
Work Step by Step
$P=\frac{V^2}R$ so $R=\frac{V^2}{P}$
$R=\frac{(100V)^2}{100W} = 100\Omega$
$P=\frac{(90V)^2}{100\Omega}=81W, 100W-81W=19W\div100W=19\%$
Electrical Engineering: Principles & Applications (6th Edition)
by Hambley, Allan R.
Published by
Prentice Hall
ISBN 10:
0133116646
ISBN 13:
978-0-13311-664-9
Chapter 1 - 1.6 - Problems - Introduction to Circuit Elements - Page 40: P1.57
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