Answer
w=48J
Work Step by Step
Power delivered to the resistor is:
$p(t)=v^2(t)/R=48\cos^2(2\pi t)=24+24\cos(4\pi t)$
Then to find energy delivered:
$w=\int_0^2 p(t)dt=\int_0^2 24+24\cos(4\pi t)dt
=[24+\frac6\pi\sin(4\pi t)]_0^2=48J$
Electrical Engineering: Principles & Applications (6th Edition)
by Hambley, Allan R.
Published by
Prentice Hall
ISBN 10:
0133116646
ISBN 13:
978-0-13311-664-9
Chapter 1 - 1.6 - Problems - Introduction to Circuit Elements - Page 40: P1.61
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