Answer
$2.71Mg/m^3$
Work Step by Step
We are given that the density (mass volume) of aluminum is $ 5.26 slug/ft^3$. We are asked to find the density in SI units, using the appropriate prefixes.
$5.26 slug/ft^3 * (\frac{1ft}{0.3048 m})^3 * \frac{14.59kg}{1slug}*\frac{1Mg}{10^3kg}=2.71Mg/m^3$
