Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 1 - General Principles - Problems - Page 15: 20

Answer

(a) $4.81\;slugs$ (b) $70.18\;kg$ (c) $689.44\;N$ (d) $25.49\;lb$ (e) $70.18\;kg$

Work Step by Step

A man weighs $155$ $lb$ on earth: $W=155$ $lb$ (a) The mass of the man $=\frac{W}{g}=\frac{155\;lb}{32.2\;ft/t^2}\approx 4.81\;slugs$ (b) $1\;slug=14.59\;kg$ The mass of the man in $kg$ is given by $=4.81\times14.59\;kg\approx 70.18\;kg$ (c) $1\;lb=4.448\;N$ The weight of the man in $newtons$ is given by $=155\times4.448\;N=689.44\;N$ (d) Weight of the man in moon is $W_m=mg_m=4.81\times5.30\;lb\approx25.49\;lb$ (e) Mass remains unchanged. Therefore mass the mass of the man in the moon is $70.18\;kg$
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