Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 21 - Three-Dimensional Kinetics of a Rigid Body - Section 21.6 - Torque-Free Motion - Problems - Page 636: 65

Answer

$$ \omega_p=1.19 \mathrm{rad} / \mathrm{s} $$

Work Step by Step

$$ \begin{aligned} & \Sigma M_s=I_z \Omega_y w_z \\ & 8(0.5)=\left[\frac{1}{2}\left(\frac{8}{32.2}\right)(0.3)^2\right] w_p(300) \\ & \omega_p=1.19 \mathrm{rad} / \mathrm{s} \end{aligned} $$
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