Answer
$$M_x=328 \mathrm{~N} \cdot \mathrm{m}
$$
Work Step by Step
$$
\begin{aligned}
& \omega_s=350 \mathrm{rad} / \mathrm{s}=\omega_z \\
& v=200 \mathrm{~km} / \mathrm{h}=\frac{200\left(10^3\right)}{3600}=55.56 \mathrm{~m} / \mathrm{s} \\
& \Omega_y=\frac{55.56}{80}=0.694 \mathrm{rad} / \mathrm{s} \\
& \Sigma M_x=I_z \Omega_y \omega_z \\
& M_x=\left[15(0.3)^2\right](0.694)(350) \\
& M_x=328 \mathrm{~N} \cdot \mathrm{m}
\end{aligned}
$$
