Answer
$d=\frac{\mu v A}{F}=\frac{(3.5\times10^{-5}*50*0.08)}{1.2}=11.7\times10^{-4}$
Work Step by Step
$\tau=\mu{\frac{v}{d}}$
$F=\tau A=\mu{\frac{v}{d}}*A$
$d=\frac{\mu v A}{F}=\frac{(3.5\times10^{-5}*50*0.08)}{1.2}=11.7\times10^{-4}$
Munson, Young and Okiishi's Fundamentals of Fluid Mechanics, Binder Ready Version 8th Edition
by Gerhart, Philip M.; Gerhart, Andrew L.; Hochstein, John I.
Published by
Wiley
ISBN 10:
1119080703
ISBN 13:
978-1-11908-070-1
Chapter 1 - Problems - Page 35: 1.76
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