Answer
$3.4\times10^{9}\,N/m^{2}$
Work Step by Step
$c=\sqrt {\frac{E_{v}}{\rho}}$ where $c$ is the speed of the sound, $E_{v}$ is the bulk modulus for the fluid and $\rho$ is the density of the fluid.
$\implies E_{v}=c^{2}\times\rho$
$ =c^{2}\times specific\, gravity\times \rho_{water}$
$=(1500\,m/s)^{2}\times1.5\times1000\,kg/m^{3}$
$=3.4\times10^{9}\,N/m^{2}$
