Answer
$\Delta \mathrm{V} \approx-0.0163 \mathrm{~m}^3$
Work Step by Step
$\Delta \mathrm{V} \approx-\frac{\mathrm{V} \Delta p}{E_v}=-\frac{(1)\left(35 \times 10^6\right)}{2.15 \times 10^9}=-0.0163 \mathrm{~m}^3$
The volume decreases.
Munson, Young and Okiishi's Fundamentals of Fluid Mechanics, Binder Ready Version 8th Edition
by Gerhart, Philip M.; Gerhart, Andrew L.; Hochstein, John I.
Published by
Wiley
ISBN 10:
1119080703
ISBN 13:
978-1-11908-070-1
Chapter 1 - Problems - Page 37: 1.96
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