Fundamentals of Engineering Thermodynamics 8th Edition

Published by Wiley
ISBN 10: 1118412931
ISBN 13: 978-1-11841-293-0

Chapter 2 - Problems: Developing Engineering Skills - Page 89: 2.82

Answer

we all know that , efficiency = $W_{cycle}$/$Q_{in}$ so , $Q_{in}$ = $W_{cycle}$/efficiency , Here , efficiency = 0.3 or 30 % , $Q_{in}$ = 500 MJ $W_{cycle}$ = efficiency $\times$ $Q_{in}$ = 0.3 $\times$ 500MJ = 150 MJ here , $W_{cycle}$ = $Q_{cycle}$ = $Q_{in}$ - $Q_{out}$ thus , $Q_{out}$ = $Q_{in}$ - $W_{cycle}$ = (500-150)MJ =350 MJ.

Work Step by Step

we all know that , efficiency = $W_{cycle}$/$Q_{in}$ so , $Q_{in}$ = $W_{cycle}$/efficiency , Here , efficiency = 0.3 or 30 % , $Q_{in}$ = 500 MJ $W_{cycle}$ = efficiency $\times$ $Q_{in}$ = 0.3 $\times$ 500MJ = 150 MJ here , $W_{cycle}$ = $Q_{cycle}$ = $Q_{in}$ - $Q_{out}$ thus , $Q_{out}$ = $Q_{in}$ - $W_{cycle}$ = (500-150)MJ =350 MJ.
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