Fundamentals of Engineering Thermodynamics 8th Edition

Published by Wiley
ISBN 10: 1118412931
ISBN 13: 978-1-11841-293-0

Chapter 2 - Problems: Developing Engineering Skills - Page 90: 2.88

Answer

we know that , (COP)beta = $Q_{in}$ /$W_{cycle}$ $W_{cycle}$ = $Q_{out}$ - $Q_{in}$ $Q_{in}$ = $Q_{out}$ - $W_{cycle}$ =(1000-300)Btu = 700 Btu. (COP)beta = 700/300 = 2.33

Work Step by Step

we know that , (COP)beta = $Q_{in}$ /$W_{cycle}$ $W_{cycle}$ = $Q_{out}$ - $Q_{in}$ $Q_{in}$ = $Q_{out}$ - $W_{cycle}$ =(1000-300)Btu = 700 Btu. (COP)beta = 700/300 = 2.33
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