Answer
We know that ,
$W_{cycle}$ = $Q_{out}$ - $Q_{in}$
here , $W_{cycle}$ = 0.15 kW and $Q_{out}$ = 0.6 kW
$Q_{in}$ = $Q_{out}$ - $W_{cycle}$ = 0.6 kW - 0.15kW
= 0.45 kW
also we know that ,
(COP)beta = $Q_{in}$ /$W_{cycle}$
putting the value of $Q_{in}$ and $W_{cycle}$ we get ,
beta = 0.45 kW/0.15 kW = 3
Work Step by Step
We know that ,
$W_{cycle}$ = $Q_{out}$ - $Q_{in}$
here , $W_{cycle}$ = 0.15 kW and $Q_{out}$ = 0.6 kW
$Q_{in}$ = $Q_{out}$ - $W_{cycle}$ = 0.6 kW - 0.15kW
= 0.45 kW
also we know that ,
(COP)beta = $Q_{in}$ /$W_{cycle}$
putting the value of $Q_{in}$ and $W_{cycle}$ we get ,
beta = 0.45 kW/0.15 kW = 3
