Materials Science and Engineering: An Introduction

Published by Wiley
ISBN 10: 1118324579
ISBN 13: 978-1-11832-457-8

Chapter 2 - Atomic Structure and Interatomic Bonding - Questions and Problems - Page 48: 2.2

Answer

$28.0854$ amu

Work Step by Step

We simply take a weighted average: $w_{28}m_{28}+w_{29}m_{29}+w_{30}m_{30}=M$ where $w_{n}$ is the atomic average and $m_{n}$ is the atomic weight of the specific silicon isotope with mass number $n$. M is the final average weight that we wish to verify. $.9223(27.9769)+.0468*(28.9765)+.0309(29.9738)=$$ 28.0854$ amu Hence, the atomic weight has been confirmed.
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